碳酸氢钠和过量澄清石灰水反应: 2Ca(OH)2+2NaHCO3=2CaCO3↓+2NaOH+H2O碳酸氢钠和适量澄清石灰水反应: Ca(OH)2+2NaHCO3=CaCO3↓+Na2CO3+2H2O
Ca(OH)2+NaHCO3===CaCO3+NaOH+H2OCa(OH)2+2NaHCO3===CaCO3+Na2CO3+2H2O