#include <stdio.h> main() {intx=1,y=0,a=0,b=0; switch(x) { case0:a++;break; case1:b++;break; }

}case2:a++;b++;break;case3:a++;b++;}printf(&quot;a=%d,b=%d/n&quot;,a,b);}
2025-03-01 19:51:36
推荐回答(4个)
回答1:

case2:a++;b++;break;
case3:a++;b++;
少了空格,应为:
case 2:a++;b++;break;
case 3:a++;b++;

回答2:

switct(1)-->case 1-->a++输出a=0;同理b=0

回答3:

}
case2:a++;b++;break;
case3:a++;b++;
}
printf("a=%d,b=%d/n",a,b);
}

回答4:

0,0