求微分方程xy"+y✀+x=0的通解

2024-11-06 21:46:26
推荐回答(1个)
回答1:

xy"+y'+x=0
xy"+y'=-x
(xy')'=-x
两边积分得
xy'=-x^2/2+C1
y'=-x/2+C1/x
两边再积分得
y=-x^2/4+C1lnx+C2