1*2*3+2*3*4+3*4*5+......+n(n+1)(n+2)

*为乘号
2024-11-05 16:23:58
推荐回答(1个)
回答1:

1×2×3+2×3×4+3×4×5+......+n(n+1)(n+2)
=1/4【1×2×3×4-0×1×2×3】+1/4【2×3×4×5-1×2×3×4】+1/4【3×4×5×6-2×3×4×5】+......+
1/4【n(n+1)(n+2)(n+3)-(n-1)n(n+1)(n+2)】
=1/4n(n+1)(n+2)(n+3)