计算:(2x^2-3x-3)⼀(x-2)-(2x^3+x^2-8x-8)⼀(x^4)=

2024-11-18 02:24:01
推荐回答(1个)
回答1:

(2x^2-3x-3)/(x-2)-(2x^3+x^2-8x-8)/(x^4)
=(x+2)(2x^2-3x-3)/(x²-4)-(2x^3+x^2-8x-8)/(x^4)
=(2x³+4x²-3x²-6x-3x-6-2x³-x²+8x+8)/(x²-4)
=(-x+2)/(x-2)(x+2)
=-1/(x+2)