简化cos(3分之π)+sin(6分之π+a)=?

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2025-03-29 05:52:59
推荐回答(2个)
回答1:

cos(3分之π)+sin(6分之π+a)
=1/2+sinπ/6cosa+cosπ/6sina
=1/2+1/2cosa+√3/2sina

回答2:

cos(3分之π+a)+sin(6分之π+a)
=1/2cosa-√3/2sina+sin(π/6)cosa+sinacos(π/6)
=1/2cosa-√3/2sina+cosa/2+√3sina/2
=cosa