(a的三次方+a的二次方*2-a*4-8)怎么因式分解成((a+2)的二次方*(a-2))

2025-03-13 16:37:56
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回答1:

a的三次方+a的二次方*2-a*4-8
a³ + 2a² - 4a - 8
= (a³ + 2a²) - (4a + 8)
= (a + 2) * a² - (a + 2) * 4
= (a + 2) * (a² - 4)
= (a + 2) * (a² - 2²)
= (a + 2) * (a+2)(a-2)
= (a+2)² * (a-2)