甲烷燃料电池:若溶液呈碱性:负极:CH4-8e-+8OH-=CO2+6H2O正极:2O2+8e-=8OH-总反应:CH4+2O2=CO2+2H2O
碱性正极:2O2+8e-=8OH-负极:CH4+10 OH-=CO3 2-(碳酸根)+3H2O+8e-总反应:CH4+2O2+2OH-=CO3 2-(碳酸根)+3H2O