(1)∵△=(2 2 )2-4×1×(-6)=4 2 ,∴x= ?2 2 ±4 2 2 ,即x1=-3 2 ,x2= 2 ;(2)原式= 2x x+1 - 2(x+3) (x+1)(x?1) ÷ x+3 (x?1)2 = 2x(x?1)?2(x+3) (x+1)(x?1) ? (x?1)2 x+3 = 2(x?3) x?1 ?(x?1)