y=2sin(2x+π/4)+1 y=sinx单调递减区间是 【2kπ-π/2,2kπ+π/2】所以2kπ-π/2<=2x+π/4<=2kπ+π/2 kπ-3π/8<=x<=kπ+π/8
y=-2sin(2x-π/4)
y递减则sin(2x-π/4)递增
sinx增区间是(2kπ-π/2,2kπ+π/2)
则2kπ-π/2<2x-π/4<2kπ+π/2
2kπ-π/4<2x<2kπ+3π/4
kπ-π/8
π/2+2kπ≤2x-π/4≤3π/2+2kπ
3π/8+kπ≤x≤7π/8+kπ
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