y=arccos(x+1)/(x-1)
y'=-1/√[1-((x+1)/(x-1))^2] * ((x+1)/(x-1))'
y'=2/√[1-((x+1)/(x-1))^2] * (1/(x-1)^2)
因为：1-((x+1)/(x-1))^2>0
(x-1)^2-(x+1)^2>0,即：-4x>0，x<0 x-1<0
y'=2/√[1-((x+1)/(x-1))^2] * (1/(x-1)^2)
=-2/[√(-4x)*(x-1)]
令x+1/x-1=g(x)
就化为了复合函数求导、
y'=-1/根号下（1-g^2（x））乘以g（x）的导数
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