求图示各梁的支座反力。

2025-03-03 05:57:39
推荐回答(1个)
回答1:

ΣMA =0, RB(4m) +20kN.m -20kN.6m -(10kN/m)(2m)(1m) =0
RB =30kN(向上)
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ΣFx =0, RAx =0
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ΣFy =0, RAy -(10kN/m)(2m) +RB -20kN =0
RAy -(10kN/m)(2m) +30kN -20kN =0
RAy =10kN(向上)
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验算:
ΣMB =0, -RAy(4m) +(10kN/m)(2m)(3m) +20kN.m -(20kN)(2m) =0
RAy =10kN(向上),与用ΣFy =0方程计得结果相同