方程两边同时除a得到a+1/a-3=0所以a+1/a-2=1
解：因为a²-3a+1=0所以a²+1=3a则a+1/a-2=a²/a+1/a-2=（a²+1）/a-2=3a/a-2=3-2=1
a²－3a＋1＝0a-3+1/a=0a+1/a=3a+1/a-2=3-2=1
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