大一高数,隐函数的导数

2025-03-07 08:46:03
推荐回答(3个)
回答1:

回答2:

y=tan(x+y)
arctany = x+y
[1/(1+y^2)] dy/dx = 1+ dy/dx
dy/dx =-(1/y^2) -1

d^2y/dx^2
= (2/y^3)(dy/dx)
=(2/y^3)(-(1/y^2) -1)
=-2( 1/y^5 + 1/y^3 )

回答3: