f(x)=sin(-2x+π/6)=-sin(2x-π/6)求f(x)的单调增区间就是求y=sin(2x-π/6)的单调减区间 令2kπ+π/2＜2x-π/6＜2kπ+3π/2,k∈Z2kπ+2π/3＜2x＜2kπ+5π/3,k∈Zkπ+2π/6＜x＜kπ+5π/6,k∈Z所以函数f(x)=sin(-2x+π/6)的单调增区间是(kπ+2π/6,kπ+5π/6),k∈Z
