x新的四次方减4x的三次方加4x的平方减9 因式分解,谢谢,帮帮 我

2025-04-04 03:15:19
推荐回答(1个)
回答1:

x^4-4x^3+4x^2-9

=x^2(x^2-4x+4)-9
=[x(x-2)]^2-9
=(x(x-2)+3)(x(x-2)-3)
=(x^2-2x+3)(x^2-2x-3)
=(x^2-2x+3)(x-3)(x+1)