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191问答库 > 内存空间地址段为3001H至7000H,则可以表示多少个字节的储存空间

内存空间地址段为3001H至7000H,则可以表示多少个字节的储存空间

4000H=16K字节怎么得到的？7000H-3001H+1 为什么要加一？

2025-03-16 23:23:22

推荐回答（3个）

回答1：

1K=10244000H=16*1024=16K加一的原因如下：例如1到10之间有多少个存储空间，共有1、2、3、4、5、6、7、8、9、10=10-1+1加一是包含起始地址的存储空间

回答2：

一个字节是八个位，256，4000/16=250，所以说少了6个，可能有其他作用

回答3：

十六进制运算4000H = 4 X 16 X 16 X 16 = 16384 ≈ 16K7000H - 3001H + 1 = 4000H = 163847000H - 3001H = 3FFFH = 16383

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