求不定积分∫1⼀[x*(x-1)^2]dx=

2024-11-06 22:27:46
推荐回答(1个)
回答1:

∫1/[x*(x-1)^2]dx

=∫(x-(x-1))/[x*(x-1)^2]dx
=∫1/(x-1)^2dx-∫1/[x*(x-1)]dx
=∫1/(x-1)^2dx-(∫1/(x-1)-1/xdx)
=∫1/(x-1)^2dx-∫dx/(x-1)+∫1/xdx
=-1/(x-1)-ln(x-1)+lnx+C