解: x的平方-y的平方-2x-4y-3
=x²-2x+1-y²-4y-4
=(x-1)²-(y+2)²
=[(x-1)+(y+2)][(x-1)-(y+2)]
=(x+y+1)(x-y-3)
x的平方-4y的平方-9z的平方-12yz
=x²-4y²-9z²-12yz
=x²-(4y²+12yz+9z²)
=x²-(2y+3z)²
=(z+2y+3z)(x-2y-3z)
祝你学习进步,如有不明可以追问.同意我的答案请采纳,O(∩_∩)O谢谢
(1)因式分解:
x²-y²-2x-4y-3
=(x-1)²-(y+2)²
=(x-1+y+2)(x-1-y-2)
=(x+y+1)(x-y-3)
(2)因式分解:
x²-4y²-9z²-12yz
=x²-(2y+3z)²
=(x+2y+3z)(x-2y-3z)
你好,很高兴回答你的问题
①x^2-y^2-2x-4y-3
=(x-1)^2-(y+2)^2
=(x+y+1)(x-y-3)
②x^2-4y^2-9z^2-12yz
=x^2-(2y+3z)^2
=(x+2y+3z)(x-2y-3z)
(x-1)^2-(y-2)^2
x^2-(2y 3z)^2