如何编写一个C语言程序，让计算机自动出四则运算计算题，要求自动出0-10之间的四则运算题，并批改结果？

少年，写好了，给你参考一下。还可以更复杂。

#include
#include
#include

#define N 10

int Test()
{
int num = 0;
int answer = 0;
int result = 0;
int m = 0;
int n = 0;
char op = 0;

int count = N;
while ( count-- )
{
m = rand() % 10;
n = rand() % 10;
op = rand() % 4;

switch ( op )
{
case 0:
op = '+';
answer = m+n;
break;
case 1:
op = '-';
answer = m-n;
break;
case 2:
op = '*';
answer = m*n;
break;
case 3:
n++;
op = '/';
answer = m/n;
break;
default:
break;
}

printf("\n题目：");
printf("%d%c%d=?\n", m, op, n);
printf("请输入答案：");
scanf("%d", &result);

if ( answer == result )
num++;
}

return num;
}

int main()
{
srand( time(NULL) );

printf("开始做题：\n");
printf("答题结束，你总共答对%d道题目。\n", Test());
return 0;
}

#include
#include
void main()
{
int a,b;
int add,sub,pro,div;
int num;
int oper;
int answer;
for(int i=0;i<10;i++) //定义出题为10个
{
a=rand()%10;
b=rand()%10;
oper=rand()%4;
switch(oper)
{
case 1:
{
printf("请输入答案:\n");
printf("%d + %d =",a,b);
scanf("%d",&answer);
if((a+b)==answer)
{
printf("\n回答正确，请继续\n");
}
}
case 2:
{
printf("请输入答案:\n");
printf("%d - %d =",a,b);
scanf("%d",&answer);
if((a-b)==answer)
{
printf("\n回答正确，请继续\n");
}
}
case 3:
{
printf("请输入答案:\n");
printf("%d * %d =",a,b);
scanf("%d",&answer);
if((a*b)==answer)
{
printf("\n回答正确，请继续\n");
}
}
case 4:
{
printf("请输入答案:\n");
printf("%d / %d =",a,b);
scanf("%d",&answer);
if((a/b)==answer)
{
printf("\n回答正确，请继续\n");
}
}
}
}
}

只要流程？