(1)直线斜率kAB=(y2-y1)/(x2-x1)把y^2=4x代入得kAB=4/(yi+y2)直线方程为y=4/(y1+y2)(x-2)代入点A(x1,y1)得y1(y1+y2)=y1^2-8得y1*y2=-8(2)设N(x3,y3)M(x4,y4)据题意,k1/k2=(y1+y2)/(y3+y4)如(1)得y2*y3=-4,y1*y4=-4所以y3=-4/y2,y4=-4/y1k1/k2=-y1y2/4=2
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