(a+1⼀2b)的平方-(a-1⼀2b)的平方+(3a-b)(9a的平方+3ab+b的平方)其中a=-1,b=2

2025-04-23 23:23:10
推荐回答(1个)
回答1:

(a+1/2b)²-(a-1/2b)²+(3a-b)(9a²+3ab+b²)
=(a+1/2b+a-1/2b)(a+1/2b-a+1/2b)+(3a-b)(9a²+3ab+b²)
=2ab+(3a-b)[(3a+b)²-3ab]
∵ a=-1,b=2
∴ ab=-2 3a+b=-1,3a-b=-5
故原式=-4-5*(1+6)
= -39