解S=a^2+b^2-c^2/4=1/2absinC即(a^2+b^2-c^2)/2=absinC即(a^2+b^2-c^2)/2ab=sinC即cosC=sinC即1=sinC/cosC=tanC即tanC=1因为C属于(0,180°)即C=45°