复数计算(1)(1+i)^7⼀1-i +(1-i)^7⼀1+i -(3-4i)(2+2i)^3⼀4+3i (2)1⼀i(√2+√2i)^5+(1

2025-03-10 15:19:27
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回答1:

(1)(1+i)^7/1-i +(1-i)^7/1+i -(3-4i)(2+2i)^3/4+3i=32+16i
(2)1/i(√2+√2i)^5+(1/1+i)^4+(1+i/1-i)^7=(8-√2)/32-21i/32