已知复数z满足z(1-i)=(1+i)2,其中i为虚数单位,则复数z的共轭复数为(  )A.1+iB.1-iC.-1+iD.

2025-04-02 15:22:24
推荐回答(1个)
回答1:

由z(1-i)=(1+i)2,得
z=

(1+i)2
1?i
2i(1+i)
2
=?1+i,
z
=?1?i

故选:D.