求不定积分∫dx⼀[(x^2)*根号下(4-x^2 )]需要过程

2024-11-15 00:22:20
推荐回答(1个)
回答1:

设x = 2sint
则dx = 2costdt
∫dx/[x²√(4-x²)]
=∫2costdt/(4sin²t * 2cost)
=-1/4 cott + C
=-√(4-x²)/4x + C