2⼀3的-2次方+(1-根号2)的0次方 -(33⼀8)的2⼀3次方+根号(3-π)平方

2025-03-10 06:26:15
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回答1:

2/3的-2次方+(1-根号2)的0次方 -(33/8)的2/3次方+根号(3-π)平方
=(2/3)^(-2)+(1-√2)^0 -(33/8)^(2/3)+√(3-π)²
=9/4+1 - [(1089)^(1/3)]/4+π-3
=1/4+3 - [(1089)^(1/3)]/4+π-3
=1/4 - [(1089)^(1/3)]/4+π
={1 - [(1089)^(1/3)]}/4+π
≈2.32+π