0.06molH2SO4，则有0.12mol的H，那么ph=-[lg(0.12)]=0.9208187539523751722774943072959
0.06molH2SO4，则有0.12mol的H，那么ph=-[lg(0.12)]=0.9208187539523751722774943072959~诚心为你解答，给个好评吧亲，谢谢啦
