∵a2,a4,a7成等比数列,∴(a1+3d)2=(a1+d)(a1+6d).∴a1=3d,∴Sn=na1+ n(n?1) 2 d= n2+5n 2 d,∴ S10 S5 = 100+50 25+25 =3.故答案为:3.