令x^2-x=x(x-1)>0x>1或 x2)(x^2-x)dx=(x^3/3-x^2/2)|(-1->0) -(x^3/3-x^2/2)|(0->1) +(x^3/3-x^2/2)|(1->2)=[(0-0)-(-1/3-1/2)]-[(1/3-1/2)-(0-0)]+[(8/3-4/2)-(1/3-1/2)]=5/6+1/6 +5/6=11/6
