已知有理数x,y,Z满足|x阧3丨+2|y+1|+7(2z+1)的平方=0,求2x+5y+10Z=

2025-04-25 20:49:01
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回答1:

由|x+3丨+2|y+1|+7(2z+1)^2=0,
得:X+3=0,Y+1=0,2Z+1=0,
解得:X=-3,Y=-1,Z=-1/2,
2x+5y+10Z
=2×(-3)+5×(-1)+10×(-1/2)
=-6-5-5
=-16。