初二下册数学分式计算题,?

急需,。
2025-03-01 02:53:36
推荐回答(1个)
回答1:

1.14a²bc/-2ac²
2.2x+8/x²-16
3.x/2a²b
÷(-2xb)
4.x-1/1
+
1+x/1
5.a²-1/a
+
a²-1/3a+1
+
1-a²/2a+1
6.x²-2xy+y²/x²-y²,其中x=110,y=10.(先化简,再求值)
7.已知(x-1)(x-2)/3x-4
=
x-1分之A
+
x-2分之B,求实数A,B。
8.(1-x)²/2x;
1.-7ab/c
2.(x-4)/2
3.-a^2*b/2*x^2*b
4.2*x/(x^2-1)
5.2*a/(a^2-1)
6.(x+y)*(x-y)/(x-y)^2=(x+y)/(X-y)=1.2
7.(3x-4)/(x-1)(x-2)=1/(x-1)+2/(x-2)
所以
A=1
B=2
8.2/(1-x)(1/x-1)