①已知f(sinx)=1-cos2x 求f(cosx) ②已知f(x+1⼀x)=x눀+1⼀x눀 求f(x-1⼀x)

2025-01-11 16:33:53
推荐回答(1个)
回答1:

f(sinx)=1-cos2x =1-(1-2(sinx)²)=2(sinx)²
求 f(x)=2x²
f(cosx)=2(cosx)²

f(x+1/x)=x²+1/x²=x²+1/x²+2-2=(x+1/x)²-2
f(x)=x²-2
f(x-1/x)=(x-1/x)²-2=x²+1/x²-4