对x^(2/3)+y^(2/3)=a^(2/3)①求导得(2/3)x^(-1/3)+(2/3)y^(-1/3)*y'=0,∴y'=-(y/x)^(1/3),在点A(a/(2√2),a/(2√2))处y'=-1,点A在曲线①上，∴曲线①在A处的切线方程是x+y-a/√2=0.法线方程是x-y=0.
