函数连续性问题求解

2025-03-04 01:52:31
推荐回答(1个)
回答1:

f(0)=0
g(x)
=f(x)/x ; x≠0
=a ; x=0
lim(x->0) g(x)
=lim(x->0) f(x)/x (0/0)
=lim(x->0) f'(x)
=f'(0)
x=0, g(x) 连续
=> a=f'(0)
(2)
g(x)
=f(x)/x ; x≠0
=f'(0) ; x=0