为什么铜有两个价电子?铜的电子排布式是3d104s1,丢掉一个电子d亚层不就正好满了?

2025-03-15 17:30:10
推荐回答(2个)
回答1:

首先明确,排电子排布式要用到四个基本的定理:能量最的原理,洪特规则,洪特规则特例,不相容定律。排铜的时候主要就是,洪特规则特例的应用。
首先铜是第29号元素,所以它的前十八个电子的排布和氩元素的原子一样,是1s2\2s2\sp6\3s2\3p6,接着是第19个电子,由于这里出现了能级交错的现象,应该先派4s的2个,然后是3d9,一般来看应该就是这样,但是这里就出现了洪特规则特例,由于要符合能量最低原理,(当轨道处于全空、半空、全充满的时候能量较低,原子较稳定),所以4s上的一个电子被激发到3d轨道上去,而激发的能量可以通过满足4s1的半充满和3d10的全充满来弥补,这样使得铜原子的能量最低,达到稳定的状态,所以铜29的电子排布式就是:
1s2\2s2\sp6\3s2\3p6\4s1\3d10,失去电子是从能量最低的地方失去,应该是3d10的而不是4S1的。

回答2:

好像是3d9 4s2吧

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