单片机流水灯问题_C编程

#include
#define uchar unsigned char
#define uint unsigned int
#define OP_WRITE 0xa0 // 器件地址以及写入操作
#define OP_READ 0xa1 // 器件地址以及读取操作
uchar code display[72]={
0xFE,0xFD,0xFB,0xF7,0xEF,0xDF,0xBF,0x7F,
0xBF,0xDF,0xEF,0xF7,0xFB,0xFD,0xFE,0xFF,
0xFE,0xFC,0xF8,0xF0,0xE0,0xC0,0x80,0x00,
0x80,0xC0,0xE0,0xF0,0xF8,0xFC,0xFE,0xFF,
0xFC,0xF9,0xF3,0xE7,0xCF,0x9F,0x3F,
0x9F,0xCF,0xE7,0xF3,0xF9,0xFC,0xFF,
0xE7,0xDB,0xBD,0x7E,0xBD,0xDB,0xE7,0xFF,
0xE7,0xC3,0x81,0x00,0x81,0xC3,0xE7,0xFF,
0xAA,0x55,0x18,0xFF,0xF0,0x0F,
0x00,0xFF,0x00,0xFF };
sbit SDA = P2^3;
sbit SCL = P2^2;
void start();
void stop();
uchar shin();
bit shout(uchar write_data);
void write_byte( uchar addr, uchar write_data);
void fill_byte(uchar fill_size,uchar fill_data);
void delayms(uint ms);
uchar read_current();
uchar read_random(uchar random_addr);
#define delayNOP(); {_nop_();_nop_();_nop_();_nop_();};
/**********************************************************/
main(void)
{
uchar i;
SDA = 1;
SCL = 1;
fill_byte(72,0xff); // 将前72字节填充0xff
for(i = 0 ; i < 72; i++) //写入显示代码到AT24C02
{
write_byte(i,display[i]);
}
for(i =0 ;i <72 ; i++) //从AT24C02移出数据送到P0口显示
{
P0 = read_random(i);
delayms(350);
}
}
/**********************************************************/
void start()
//开始位
{
SDA = 1;
SCL = 1;
delayNOP();
SDA = 0;
delayNOP();
SCL = 0;
}
/**********************************************************/
void stop()
// 停止位
{
SDA = 0;
delayNOP();
SCL = 1;
delayNOP();
SDA = 1;
}
/**********************************************************/
uchar shin()
// 从AT24C02移出数据到MCU
{
uchar i,read_data;
for(i = 0; i < 8; i++)
{
SCL = 1;
read_data <<= 1;
read_data |= SDA;
SCL = 0;
}
return(read_data);
}
/**********************************************************/
bit shout(uchar write_data)
// 从MCU移出数据到AT24C02
{
uchar i;
bit ack_bit;
for(i = 0; i < 8; i++) // 循环移入8个位
{
SDA = (bit)(write_data & 0x80);
_nop_();
SCL = 1;
delayNOP();
SCL = 0;
write_data <<= 1;
}
SDA = 1; // 读取应答
delayNOP();
SCL = 1;
delayNOP();
ack_bit = SDA;
SCL = 0;
return ack_bit; // 返回AT24C02应答位
}
/**********************************************************/
void write_byte(uchar addr, uchar write_data)
// 在指定地址addr处写入数据write_data
{
start();
shout(OP_WRITE);
shout(addr);
shout(write_data);
stop();
delayms(10); // 写入周期
}
/**********************************************************/
void fill_byte(uchar fill_size,uchar fill_data)
// 填充数据fill_data到EEPROM内fill_size字节
{
uchar i;
for(i = 0; i < fill_size; i++)
{
write_byte(i, fill_data);
}
}
/**********************************************************/
uchar read_current()
// 在当前地址读取
{
uchar read_data;
start();
shout(OP_READ);
read_data = shin();
stop();
return read_data;
}
/**********************************************************/
uchar read_random(uchar random_addr)
// 在指定地址读取
{
start();
shout(OP_WRITE);
shout(random_addr);
return(read_current());
}
/**********************************************************/
void delayms(uint ms)
// 延时子程序
{
uchar k;
while(ms--)
{
for(k = 0; k < 120; k++);
}
}
你要自己改哦 因为型号，发光的个性也不一样啊

我把我以前写的给你，你自己调试一下看
#include
#include
#define uint unsigned int
#define uchar unsigned char

void delay(uint) ;
uchar temp,i;

void main()
{

while(1)
{
for(b=0;b<2;b++)
{
if(temp!=0x00)
{
temp=0x7f;
P1=temp;
delay(1000);
temp=0x80;

for(i=0;i<7;i++)
{
temp=~_iror_(temp,1);
delay(1000);
P1= temp;
delay(1000);
temp=~temp;
}

}
temp=0xfe;
P1=temp;
delay(1000);
temp=0x01;
for(i=0;i<7;i++)
{
temp=~_irol_(temp,1);
delay(1000);
P1= temp;
delay(1000);
temp=~temp;
}

}

temp=0xff;
P1=temp ;
delay(8000);
temp=0;
delay(1000);
temp=0xff;
delay(1000);
temp=0;
delay(1000);
temp=0xff;
delay(1000);
}

}

void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=120;y>0;y--);
}

这个最简单的办法是用一个数组 一次循环就搞定了 就是你这个间隔一秒 要用定时器来做？

我这里有啊，分少了。