代数式x-(x+1)/2与(x-2)/3-2的值互为相反数:x-(x+1)/2=-[(x-2)/3-2]6x-3(x+1)=-2(x-2)+126x-3x-3=-2x+4+123x+2x=16+35x=19x=19/5当x=(19/5)时,代数式x-(x+1)/2与(x-2)/3-2的值互为相反数.
