高数向量求详解

2024-11-03 02:26:13
推荐回答(1个)
回答1:

m=2a+3b, n=3a-b,|a|=2, |b|=1, axb=π/3
To find :|mxn|
solution :
mxn
=(2a+3b)x (3a-b)
=-2(axb) +9(bxa)
=-11axb
|mxn| =11|axb| = 11π/3