已知x十2y十3z=54,3x十2y十2z=47,2x十2y十z=31,那么代数式x十y十z的值

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2025-04-03 12:56:31
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回答1:

x+2y+3z=54 (1)
3x+2y+2z=47 (2)
2x+2y+z=31 (3)
(1)+(2)+(3)得:
6x+6y+6z=54+47+31
6(x+y+z)=132
x+y+z=22