已知m^2+m-1=0,求代数式m^3+2m^2+2004的值

2025-04-06 07:47:48
推荐回答(1个)
回答1:

m^3+2m^2+2004
m(1-m)+2(1-m)+2004
=-m^2-m+2006
=-(1-m)-m+2006
=2005