基于8051单片机的数字钟设计

2025-01-07 05:20:08

推荐回答（3个）

回答1：

1602液晶显示
你的单片机原理图没发
程序很依赖硬件的哦
这个程序你查考下，有三个键按可以修改时间的。

#include
#define uchar unsigned char
#define uint unsigned int
sbit dula=P2^6;
sbit wela=P2^7;
sbit rs=P3^5;
sbit lcden=P3^4;
sbit s1=P3^0;
sbit s2=P3^1;
sbit s3=P3^2;
sbit rd=P3^7;
uchar count,s1num;
char miao,shi,fen;
uchar code table[]=" 2009-5-17 MON"; \\
uchar code table1[]=" 00:00:00"; \\自己设下
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}

void write_com(uchar com)
{
rs=0;
lcden=0;
P0=com;
delay(5);
lcden=1;
delay(5);
lcden=0;
}

void write_date(uchar date)
{
rs=1;
lcden=0;
P0=date;
delay(5);
lcden=1;
delay(5);
lcden=0;
}

void init()
{
uchar num;
dula=0;
wela=0;
lcden=0;
// fen=59;
// miao=53;
// shi=23;
write_com(0x38);
write_com(0x0c);
write_com(0x06);
write_com(0x01);
write_com(0x80);
for(num=0;num<15;num++)
{
write_date(table[num]);
delay(5);
}
write_com(0x80+0x40);
for(num=0;num<12;num++)
{
write_date(table1[num]);
delay(5);
}
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1;
TR0=1;
}

void write_sfm(uchar add,uchar date)
{
uchar shi,ge;
shi=date/10;
ge=date%10;
write_com(0x80+0x40+add);
write_date(0x30+shi);
write_date(0x30+ge);
}

void keyscan()
{
rd=0;
if(s1==0)
{
delay(5);
if(s1==0)
{ s1num++;
while(!s1);
if(s1num==1)
{
TR0=0;
write_com(0x80+0x40+10);
write_com(0x0f);
}
}
if(s1num==2)
{
write_com(0x80+0x40+7);
}
if(s1num==3)
{
write_com(0x80+0x40+4);
}
if(s1num==4)
{
s1num=0;
write_com(0x0c);
TR0=1;
}

}
if(s1num!=0)
{
if(s2==0)
{
delay(5);
if(s2==0)
{
while(!s2);
if(s1num==1)
{
miao++;
if(miao==60)
miao=0;
write_sfm(10,miao);
write_com(0x80+0x40+10);

}
if(s1num==2)
{
fen++;
if(fen==60)
fen=0;
write_sfm(7,fen);
write_com(0x80+0x40+7);
}
if(s1num==3)
{
shi++;
if(shi==24)
shi=0;
write_sfm(4,shi);
write_com(0x80+0x40+4);
}
}
}
if(s3==0)
{
delay(5);
if(s3==0)
{
while(!s3);
if(s1num==1)
{
/* if(miao==0)
{
miao=59;
write_sfm(10,miao);
write_com(0x80+0x40+10);
}*/
miao--;
if(miao==-1)
miao=59;
write_sfm(10,miao);
write_com(0x80+0x40+10);
}
if(s1num==2)
{
fen--;
if(fen==-1)
fen=59;
write_sfm(7,fen);
write_com(0x80+0x40+7);
}
if(s1num==3)
{
shi--;
if(shi==-1)
shi=23;
write_sfm(4,shi);
write_com(0x80+0x40+4);
}
}
}
}
}
void main()
{
init();
while(1)
{
keyscan();

}
// while(1);
}

void timer0() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
count++;
if(count==18)
{
count=0;
miao++;
if(miao==60)
{
miao=0;
fen++;
if(fen==60)
{
fen=0;
shi++;
if(shi==24)
{
shi=0;
}
write_sfm(4,shi);
}
write_sfm(7,fen);
}
write_sfm(10,miao);

}
}

回答2：

楼上的程序能用，我测试过了，图不要看了，已经很清楚了
sbit dula=P2^6; 段选
sbit wela=P2^7; 位选（应该用了74ls535）
sbit rs=P3^5;
sbit lcden=P3^4; 液晶的收发位（图我给你）
sbit s1=P3^0;
sbit s2=P3^1;
sbit s3=P3^2; 三个按键
sbit rd=P3^7;
290643832

回答3：

1602液晶显示
你的单片机原理图没发
程序很依赖硬件的哦
这个程序你查考下，有三个键按可以修改时间的。
#include
#define
uchar
unsigned
char
#define
uint
unsigned
int
sbit
dula=P2^6;
sbit
wela=P2^7;
sbit
rs=P3^5;
sbit
lcden=P3^4;
sbit
s1=P3^0;
sbit
s2=P3^1;
sbit
s3=P3^2;
sbit
rd=P3^7;
uchar
count,s1num;
char
miao,shi,fen;
uchar
code
table[]="
2009-5-17
MON";
\\
uchar
code
table1[]="
00:00:00";
\\自己设下
void
delay(uint
z)
{
uint
x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void
write_com(uchar
com)
{
rs=0;
lcden=0;
P0=com;
delay(5);
lcden=1;
delay(5);
lcden=0;
}
void
write_date(uchar
date)
{
rs=1;
lcden=0;
P0=date;
delay(5);
lcden=1;
delay(5);
lcden=0;
}
void
init()
{
uchar
num;
dula=0;
wela=0;
lcden=0;
//
fen=59;
//
miao=53;
//
shi=23;
write_com(0x38);
write_com(0x0c);
write_com(0x06);
write_com(0x01);
write_com(0x80);
for(num=0;num<15;num++)
{
write_date(table[num]);
delay(5);
}
write_com(0x80+0x40);
for(num=0;num<12;num++)
{
write_date(table1[num]);
delay(5);
}
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1;
TR0=1;
}
void
write_sfm(uchar
add,uchar
date)
{
uchar
shi,ge;
shi=date/10;
ge=date%10;
write_com(0x80+0x40+add);
write_date(0x30+shi);
write_date(0x30+ge);
}
void
keyscan()
{
rd=0;
if(s1==0)
{
delay(5);
if(s1==0)
{
s1num++;
while(!s1);
if(s1num==1)
{
TR0=0;
write_com(0x80+0x40+10);
write_com(0x0f);
}
}
if(s1num==2)
{
write_com(0x80+0x40+7);
}
if(s1num==3)
{
write_com(0x80+0x40+4);
}
if(s1num==4)
{
s1num=0;
write_com(0x0c);
TR0=1;
}
}
if(s1num!=0)
{
if(s2==0)
{
delay(5);
if(s2==0)
{
while(!s2);
if(s1num==1)
{
miao++;
if(miao==60)
miao=0;
write_sfm(10,miao);
write_com(0x80+0x40+10);
}
if(s1num==2)
{
fen++;
if(fen==60)
fen=0;
write_sfm(7,fen);
write_com(0x80+0x40+7);
}
if(s1num==3)
{
shi++;
if(shi==24)
shi=0;
write_sfm(4,shi);
write_com(0x80+0x40+4);
}
}
}
if(s3==0)
{
delay(5);
if(s3==0)
{
while(!s3);
if(s1num==1)
{
/*
if(miao==0)
{
miao=59;
write_sfm(10,miao);
write_com(0x80+0x40+10);
}*/
miao--;
if(miao==-1)
miao=59;
write_sfm(10,miao);
write_com(0x80+0x40+10);
}
if(s1num==2)
{
fen--;
if(fen==-1)
fen=59;
write_sfm(7,fen);
write_com(0x80+0x40+7);
}
if(s1num==3)
{
shi--;
if(shi==-1)
shi=23;
write_sfm(4,shi);
write_com(0x80+0x40+4);
}
}
}
}
}
void
main()
{
init();
while(1)
{
keyscan();
}
//
while(1);
}
void
timer0()
interrupt
1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
count++;
if(count==18)
{
count=0;
miao++;
if(miao==60)
{
miao=0;
fen++;
if(fen==60)
{
fen=0;
shi++;
if(shi==24)
{
shi=0;
}
write_sfm(4,shi);
}
write_sfm(7,fen);
}
write_sfm(10,miao);
}
}