191问答库 > 现有两个灯泡L1、L2，分别标有“10V 10W”和“9V 5.4W”的字样．当将它们串联使用时，电路两端允许加的最

现有两个灯泡L1、L2，分别标有“10V 10W”和“9V 5.4W”的字样．当将它们串联使用时，电路两端允许加的最

2025-03-16 23:58:50
推荐回答（1个）
回答1：

（1）灯泡L1的额定电流I1=
P1
U1
=
10W
10V
=1A，灯泡L2的额定电流I2=
P2
U2
=
5.4W
9V
=0.6A，
当把它们串联起来时，电路中的电流只能取0.6A，
灯泡L1的R1=
U1
I1
=
10V
1A
=10Ω，灯泡L2的电阻R2=
U2
I2
=
9V
0.6A
=15Ω，
串联的总电阻：R=R1+R2=10Ω+15Ω=25Ω，
则串联电路的总电压：U=I2R=0.6A×25Ω=15V．
（2）当把它们并联起来时，电路中的电源电压只能取灯泡L2的额定电压9V：
R1中的电流：I1′=
U2
R1
=
9V
10Ω
=0.9A，
R2中的电流：I2′=
U2
R2
=
9V
15Ω
=0.6A，
则并联电路的总电流：I=I1′+I2′=0.9A+0.6A=1.5A．
（3）电路消耗的最大功率P=U2I=9V×1.5A=13.5W．
故答案为：15；1.5；13.5．

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