a+b=1 a눀+b눀=2 a的七次方加b的七次方等于多少?

2024-11-07 01:30:00
推荐回答(1个)
回答1:

a^2+b^2=(a+b)^2-2ab=1-2ab=2
ab=-1/2
所以方程x^2-x-1/2=0的解为a,b
所以a^2=a+1/2
b^2=b+1/2
化简a^7=a(a^2)^3=a(a+1/2)^3=41/8a+15/8
同理化简b^7=41/8b+15/8
a^7+b^7=41/8(a+b)+15/8+15/8=71/8