设A,B为同级正交矩阵,且丨A丨=-丨B丨,证明:丨A+B丨=0

2025-02-22 13:34:14
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回答1:

A,B都是正交矩阵,
∴|A|=±1,|B|=±1

∵|A|=-|B|
不妨设|A|=1,|B|=-1

|A+B|=|A+A·A^T·B|
=|A(E+A^T·B)|
=|A|·|E+A^T·B|
=|E+A^T·B|
=|(E+B^T·A)^T|
=|E+B^T·A|

|A+B|=|B·B^T·A+B|
=|B(B^T·A+E)|
=|B|·|B^T·A+E|
=-|B^T·A+E|

∴|B^T·A+E|=-|B^T·A+E|
∴|B^T·A+E|=0
∴|A+B|=0