求曲线y=e^(-x)与直线x=0,x=1,y=0所围成的平面图形绕Y轴旋转一周...

2024-11-17 19:22:28
推荐回答(1个)
回答1:

x
=
0,y
=
e^0
=
1
x
=
1,y
=
1/e
绕y轴旋转,用y做自变量较方便:y
=
e^(-x),x
=
-lny
0
<
y
<
1/e时,旋转体为:截面为半径=1,高为1/e的圆柱,体积V1
=
π*1²*1/e
=
π/e
1/e
<
y
<
1处,旋转体截面为以|-lny|为半径的圆,V2
=
∫πln²ydy
=
πy(ln²y
-
2lny
+
2)
(1/e
->1)
=
π(0
-
0
+2)
-
π(1
+
2
+
2)/e
=

-
5π/e
V
=
V1
+V2
=
π/e
+

-
5π/e
=

-
4π/e