设A,B,C为三个随机事件,证明加法公式 P(A+B+C)=pA+pB+pC-pAB-pAC-pB

2025-01-05 12:16:25
推荐回答(2个)
回答1:

P(A+B+C)=P(A+B)+P(C)-P((A+B)C)
=P(A)+P(B)-P(AB)+P(C)-P(AC+BC)
=P(A)+P(B)+P(C)-P(AB)-[P(AC)+P(BC)-P(ABC)]
=P(A)+P(B)+P(C)-P(AB)-P(BC)-P(AC)+P(ABC)

回答2: