1.先化简再求值,2-(2a+b⼀a+b)÷4a눀+4ab+b눀⼀a눀-b눀,其中a=-1,b=1⼀2

2024-11-20 21:32:02
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回答1:

2-(2a+b/a+b)÷4a²+4ab+b²/a²-b²
=2-(2a+b/a+b)÷(2a+b)²/(a+b)(a-b)
=2-(2a+b/a+b)×(a+b)(a-b)/(2a+b)²
=2-(a-b/2a+b)
代入
原式=2-(-1-1/2)/(-2+1/2)
=2-1
=1