AP = A(X,AX,A^2X) = (AX,A^2X,A^3X) = (AX,A^2X,3AX-2A^2X) = PBB =0 0 01 0 30 1 -2因为 X,AX,A^2X 线性无关所以 P=(X,AX,A^2X) 可逆所以 P^-1AP = B所以 |A| = |B| = 0
